NEET Chemistry Organic Preparations MCQ Question
In the reaction 6NaI + 4H2SO4 → 3I2 + 4H2O + S + 3Na2SO4, how many moles of iodine (I2) are produced when 0.5 moles of NaI react completely?
0.25 moles
0.5 moles
0.75 moles
1.0 moles
Correct Answer
Detailed Explanation
The stoichiometry of the reaction shows that 6 moles of NaI produce 3 moles of I2. Therefore, 0.5 moles of NaI will produce (0.5/6)*3 = 0.25 moles of I2.
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