Chemistry-Nernst Equation

NEET Chemistry Nernst Equation MCQ Question

Type: MCQ-diagram based-Hard-Class 12

Consider a galvanic cell where the following reaction occurs: Zn(s)+Cu2+(aq)Zn2+(aq)+Cu(s)\text{Zn(s)} + \text{Cu}^{2+}(aq) \rightarrow \text{Zn}^{2+}(aq) + \text{Cu(s)}. The cell is set up with [Cu2+]=0.5M[\text{Cu}^{2+}] = 0.5 \text{M} and [Zn2+]=0.01M[\text{Zn}^{2+}] = 0.01 \text{M}. Using the Nernst equation, which of the following expressions correctly represents the cell potential EcellE_{cell}?

Question diagram
A

Ecell=Ecell0.0592log(0.010.5)E_{cell} = E^{\circ}_{cell} - \frac{0.059}{2} \log \left( \frac{0.01}{0.5} \right)

B

Ecell=Ecell0.0592log(0.50.01)E_{cell} = E^{\circ}_{cell} - \frac{0.059}{2} \log \left( \frac{0.5}{0.01} \right)

C

Ecell=Ecell+0.0592log(0.50.01)E_{cell} = E^{\circ}_{cell} + \frac{0.059}{2} \log \left( \frac{0.5}{0.01} \right)

D

Ecell=Ecell+0.0592log(0.010.5)E_{cell} = E^{\circ}_{cell} + \frac{0.059}{2} \log \left( \frac{0.01}{0.5} \right)

Correct Answer

Option A

Detailed Explanation

According to the Nernst equation, Ecell=Ecell0.059nlog([Zn2+][Cu2+])E_{cell} = E^{\circ}_{cell} - \frac{0.059}{n} \log \left( \frac{[\text{Zn}^{2+}]}{[\text{Cu}^{2+}]} \right), where n is the number of electrons transferred. Here, n = 2.

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