NEET Chemistry Faraday's Laws MCQ Question
An electric charge of 5 Faradays is passed through three electrolytes AgNO₃, CuSO₄ and FeCl₃ solution. The grams of each metal liberated at cathode will be
Ag = 10.8 g, Cu = 12.7 g, Fe = 1.11 g
Ag = 540 g, Cu = 367.5 g, Fe = 325 g
Ag = 108 g, Cu = 63.5 g, Fe = 56 g
Ag = 540 g, Cu = 158.8 g, Fe = 93.3 g
Correct Answer
Detailed Explanation
The mass of metal liberated is calculated using Faraday's laws of electrolysis: mass = (Equivalent weight × Current × Time) / Faraday's constant. For 5 Faradays, the mass is directly proportional to the equivalent weight.
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