Chemistry-(general)
NEET Chemistry (general) MCQ Question
Type: MCQ-numerical-Hard-Class 12
Given the limiting molar conductivities (Λ₀) for NaCl, HCl, and NaAc as 126.4, 425.9, and 91.0 S cm² mol⁻¹ respectively, and the conductivity of 0.001028 mol L⁻¹ acetic acid as 4.95 × 10⁻⁵ S cm⁻¹, calculate the degree of dissociation (α) of acetic acid at this concentration.
A
0.1233
B
0.3921
C
0.2783
D
0.0512
Correct Answer
Option A
Detailed Explanation
The degree of dissociation (α) is calculated using α = Λ_m / Λ₀, where Λ_m is the molar conductivity at the given concentration (48.15 S cm² mol⁻¹) and Λ₀ is the limiting molar conductivity of acetic acid (390.5 S cm² mol⁻¹). From the calculation, α = 48.15 / 390.5 = 0.1233.
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