Chemistry-(general)
NEET Chemistry (general) MCQ Question
Type: MCQ-numerical-Medium-Class 12
Given the conductivity of a 0.001028 mol L⁻¹ acetic acid solution is 4.95 × 10⁻⁵ S cm⁻¹ and its limiting molar conductivity is 390.5 S cm² mol⁻¹, calculate the degree of dissociation (α) of acetic acid in this solution.
A
0.1233
B
0.2500
C
0.0750
D
0.5000
Correct Answer
Option A
Detailed Explanation
The degree of dissociation (α) is calculated using α = Λm / Λ°m, where Λm = κ × 1000 / c = 48.15 S cm² mol⁻¹ and Λ°m = 390.5 S cm² mol⁻¹, giving α = 48.15 / 390.5 = 0.1233.
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