Calculate the dissociation constant (K) for acetic acid if its conductivity is 7.896 × 10⁻⁵ S cm⁻¹ and concentration is 0.00241 M given that its molar conductivity at infinite dilution is 390.5 S cm² mol⁻¹.
A
75 × 10⁻⁵ mol L⁻¹
B
68 × 10⁻⁵ mol L⁻¹
C
78 × 10⁻⁵ mol L⁻¹
D
80 × 10⁻⁵ mol L⁻¹

Question

Calculate the dissociation constant (K) for acetic acid if its conductivity is 7.896 × 10⁻⁵ S cm⁻¹ and concentration is 0.00241 M given that its molar conductivity at infinite dilution is 390.5 S cm² mol⁻¹.

A

75 × 10⁻⁵ mol L⁻¹

B

68 × 10⁻⁵ mol L⁻¹

C

78 × 10⁻⁵ mol L⁻¹

D

80 × 10⁻⁵ mol L⁻¹

Accepted Answer

78 × 10⁻⁵ mol L⁻¹

Answer

75 × 10⁻⁵ mol L⁻¹

Answer

68 × 10⁻⁵ mol L⁻¹

Answer

80 × 10⁻⁵ mol L⁻¹

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