NEET Chemistry Electrolytic Cells MCQ Question
In an electrolytic cell, how much charge is required to deposit 0.5 mol of copper on the cathode from a copper(II) sulfate solution?
48,250 C
96,500 C
24,125 C
193,000 C
Correct Answer
Detailed Explanation
The charge required can be calculated using Faraday's law of electrolysis, which states that 1 mole of a substance is deposited or dissolved by 2 Faradays (2 x 96,485 C) for copper. Therefore, for 0.5 mol, the charge is 0.5 x 2 x 96,485 C = 48,250 C.
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