Back to Practice

Chemistry-Crystal Field Theory

NEET Chemistry Crystal Field Theory MCQ Question

Type: MCQ-numerical-Easy-Class 12

Calculate the number of unpaired electrons in the [MnBr4]2– complex ion if its spin-only magnetic moment is given as 5.9 BM.

A

5 unpaired electrons

B

4 unpaired electrons

C

3 unpaired electrons

D

2 unpaired electrons

Correct Answer

Option A

Detailed Explanation

The spin-only magnetic moment formula is $\mu = \sqrt{n(n+2)}$ BM, where $n$ is the number of unpaired electrons. Solving $\sqrt{n(n+2)} = 5.9$ gives $n = 5$ .

Found an issue with this question?

Explore More Questions

All Chemistry Questions Coordination Compounds Questions