NEET Chemistry Rate of Reaction MCQ Question
A plot is provided where the y-axis is ln k and the x-axis is 1/T. The slope of the line is labeled as -Ea/R, and the intercept as ln A. Based on this plot, which of the following statements is correct regarding the activation energy (Ea) and the pre-exponential factor (A)?
The slope of the plot is negative, indicating a positive activation energy.
The intercept ln A is inversely proportional to the activation energy.
A higher intercept value corresponds to a lower pre-exponential factor.
The plot can be used to calculate the activation energy only if the reaction is zeroth-order.
Correct Answer
Detailed Explanation
The slope of the plot between ln k and 1/T is -Ea/R, which indicates that the activation energy Ea is positive, as a negative slope results from a positive Ea divided by R.
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