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Chemistry-Rate of Reaction

NEET Chemistry Rate of Reaction MCQ Question

Type: MCQ-numerical-Medium-Class 12

For a first-order reaction with a rate constant k = 60 s⁻¹, what is the time taken for the reactant concentration to decrease to 1/16th of its initial value?

A

0.046 s

B

0.115 s

C

0.231 s

D

0.693 s

Correct Answer

Option C

Detailed Explanation

Using the first-order reaction formula: t=2.303klog⁡[R]0[R]t = \frac{2.303}{k} \log \frac{[R]_0}{[R]} with [R]=[R]016[R] = \frac{[R]_0}{16}, we get t=2.30360×log⁡16≈0.231 st = \frac{2.303}{60} \times \log 16 \approx 0.231 \text{ s}.

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