Chemistry-Order of Reaction

NEET Chemistry Order of Reaction MCQ Question

Type: MCQ-numerical-Medium-Class 12

For a reaction where the concentration of reactant [R] decreases from [R]0 to [R]1 over time t1 with a first-order rate constant k, compute the rate constant if ln[R]0 - ln[R]1 = 0.693 and t1 = 10 seconds.

A

0.0693 s^-1

B

0.0693 mol/L

C

0.693 s^-1

D

0.693 mol/L

Correct Answer

Option A

Detailed Explanation

Using the first-order rate equation ln[R]1 - ln[R]0 = -k(t1), we rearrange to find k = (ln[R]0 - ln[R]1) / t1. Given ln[R]0 - ln[R]1 = 0.693 and t1 = 10 seconds, k = 0.693 / 10 = 0.0693 s^-1.

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