Chemistry-Order of Reaction
NEET Chemistry Order of Reaction MCQ Question
Type: MCQ-numerical-Easy-Class 12
Given a first-order reaction, if the concentration of the reactant decreases from 0.8 M to 0.2 M in 40 minutes, what is the rate constant (k) of the reaction?
A
0.03465 min⁻¹
B
0.01732 min⁻¹
C
0.00577 min⁻¹
D
0.02310 min⁻¹
Correct Answer
Option A
Detailed Explanation
For a first-order reaction, the rate constant k can be calculated using the formula ln([R]₀/[R]) = kt. Here, ln(0.8/0.2) = k * 40 min, solving gives k ≈ 0.03465 min⁻¹.
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