Chemistry-(general)
NEET Chemistry (general) MCQ Question
Type: MCQ-diagram based-Hard-Class 12
Consider a reaction diagram where the partial pressures of reactants and products are plotted against time for the reaction A(g) → B(g) + C(g). If the initial pressure of A is p_i atm and decreases by x atm at time t, what would be the expression for the rate constant k of this reaction?
A
k = (2.303/t) log((p_i)/(2p_i - p_t))
B
k = (2.303/t) log((p_i - x)/(p_t))
C
k = (2.303/t) log((p_i)/(p_i + x))
D
k = (2.303/t) log((p_t)/(p_i - x))
Correct Answer
Option A
Detailed Explanation
According to the NCERT context, the rate constant for a first-order reaction can be calculated using the relation k = (2.303/t) log(p_i/p_t). However, due to the stoichiometry of the reaction, the correct expression for this situation is k = (2.303/t) log((p_i)/(2p_i - p_t)).
Found an issue with this question?