Chemistry-Enthalpy
NEET Chemistry Enthalpy MCQ Question
Type: MCQ-fact-Hard-Class 11
What is the enthalpy change, ∆ vap H , required to evaporate 18 g of water at 298 K?
A
44.01 kJ
B
41.53 kJ
C
2.48 kJ
D
6.00 kJ
Correct Answer
Option A
Detailed Explanation
The heat supplied to evaporate 18 g of water at 298 K is calculated as n × ∆ vap H = (1 mol) × (44.01 kJ mol –1 ) = 44.01 kJ, as stated in the NCERT context.
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