Chemistry-Enthalpy
NEET Chemistry Enthalpy MCQ Question
Type: MCQ-numerical-Hard-Class 11
Calculate the heat required to vaporize 2 moles of water at its boiling point under standard pressure.
A
40.79 kJ
B
81.58 kJ
C
20.39 kJ
D
121.58 kJ
Correct Answer
Option B
Detailed Explanation
The standard enthalpy of vaporization for water is given as 40.79 kJ/mol. For 2 moles, the heat required is 2 x 40.79 kJ/mol = 81.58 kJ.
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