NEET2023Chemistry-Thermodynamics

NEET 2023 Chemistry Enthalpy and Internal Energy MCQ Question

Type: MCQ-conceptual-Medium-Class 11

Which amongst the following options is the correct relation between change in enthalpy and change in internal energy?

A

ΔH = ΔU - Δn_g RT

B

ΔH = ΔU + Δn_g RT

C

ΔH - ΔU = -ΔnRT

D

ΔH + ΔU = ΔnR

Correct Answer

Option B

Detailed Explanation

To understand the relationship between the change in enthalpy (ΔH\Delta H) and the change in internal energy (ΔU\Delta U) in thermodynamics, we need to consider the definitions and the derived relationships that involve the number of moles of gas and temperature.

Explanation of the Correct Answer (B)

The correct relationship between the change in enthalpy and the change in internal energy is given by:

ΔHΔU=ΔngRT\Delta H - \Delta U = -\Delta n_g RT

Where:

  • ΔH\Delta H is the change in enthalpy.
  • ΔU\Delta U is the change in internal energy.
  • Δng\Delta n_g is the change in the number of moles of gas during the reaction.
  • RR is the universal gas constant.
  • TT is the temperature in Kelvin.

This equation can be derived from the definition of enthalpy:

H=U+PVH = U + PV

For constant pressure processes, we can express the change in enthalpy as:

ΔH=ΔU+Δ(PV)\Delta H = \Delta U + \Delta (PV)

Using the ideal gas law, for an ideal gas, we can express PV=nRTPV = nRT. If the number of moles of gas changes during a reaction (Δng\Delta n_g), then:

Δ(PV)=ΔngRT\Delta (PV) = \Delta n_g RT

Substituting this back into the expression for ΔH\Delta H, we get:

ΔH=ΔU+ΔngRT\Delta H = \Delta U + \Delta n_g RT

Rearranging this gives us the correct relationship:

ΔHΔU=ΔngRT\Delta H - \Delta U = \Delta n_g RT

However, this is often presented in the context of reactions where gases are produced or consumed, leading to the negative sign when considering the change in moles of gases, thus:

ΔHΔU=ΔngRT\Delta H - \Delta U = -\Delta n_g RT

Clarification of Incorrect Options

Option A: ΔH=ΔU+ΔngRT\Delta H = \Delta U + \Delta n_g RT

This is a misrepresentation of the relationship. While it resembles the correct equation, it does not account for the sign of the change in moles of gases. The correct form has a negative sign associated with the change in moles.

Option C: ΔH+ΔU=ΔnR\Delta H + \Delta U = \Delta n R

This option is incorrect because it suggests a direct addition of ΔH\Delta H and ΔU\Delta U equating to ΔnR\Delta nR. This does not reflect the established relationship in thermodynamics and misrepresents the roles of enthalpy and internal energy in terms of gas moles.

Option D: ΔH=ΔUΔngRT\Delta H = \Delta U - \Delta n_g RT

This equation is also incorrect because it has the wrong sign in front of the term ΔngRT\Delta n_g RT. It implies that the change in enthalpy is less than the change in internal energy by the product of the change in gas moles and temperature, which contradicts the correct relationship established in thermodynamic principles.

Summary

In summary, the correct relationship is:

ΔHΔU=ΔngRT\Delta H - \Delta U = -\Delta n_g RT

This reflects that changes in enthalpy and internal energy are interconnected via the behavior of gases in a reaction. The incorrect options either misrepresent the sign or misinterpret the relationship altogether. Understanding these concepts is crucial for solving problems related to thermodynamics in the NEET/JEE examinations.

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