RE-NEET2024Chemistry-Thermodynamics
RE-NEET 2024 Chemistry Enthalpy and Internal Energy MCQ Question
Type: MCQ-numerical-Medium-Class 11
For the following reaction at 300 K A₂(g) + 3B₂(g) → 2AB₃(g) the enthalpy change is +15 kJ, then the internal energy change is:
A
19988.4 J
B
200 J
C
1999 J
D
1.9988 kJ
Correct Answer
Option 1
Detailed Explanation
The internal energy change is calculated using the formula ΔU = ΔH - ΔnRT, where Δn is the change in moles of gas.
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