NEET Chemistry Solubility Product MCQ Question
The solubility of BaSO₄ in water is 2.42 × 10⁻³ g L⁻¹ at 298 K. The value of its solubility product (Ksp) will be (Given molar mass of BaSO₄ = 233 g mol⁻¹)
08 × 10⁻¹⁰ mol² L⁻²
08 × 10⁻¹² mol² L⁻²
08 × 10⁻¹⁴ mol² L⁻²
08 × 10⁻⁸ mol² L⁻²
Correct Answer
Detailed Explanation
Ksp is calculated using the solubility in mol/L, which is derived from the given solubility in g/L.
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