NEET Chemistry Ionic Equilibrium MCQ Question
A 0.002 M solution of a weak base has a pH of 9.8. What is the ionization constant (K_b) of the base?
51 × 10^-5
58 × 10^-5
16 × 10^-5
5.01 × 10^-5
Correct Answer
Detailed Explanation
From the pH, calculate [H^+] as antilog(-9.8). Use [OH^-] = K_w / [H^+], then use the ionization equilibrium to find K_b = [OH^-]^2 / [base].
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