NEET Chemistry Ionic Equilibrium MCQ Question
What is the equilibrium constant expression for the dissociation of acetic acid (HAc) in water?
K_a = [H^+][Ac^-]/[HAc]
K_a = [HAc]/[H^+][Ac^-]
K_a = [Ac^-]/[H^+][HAc]
K_a = [H^+][HAc]/[Ac^-]
Correct Answer
Detailed Explanation
The equilibrium constant expression for the dissociation of acetic acid is given by K_a = [H^+][Ac^-]/[HAc], which reflects the concentrations of the products and reactants at equilibrium.
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