NEET Chemistry Chemical Equilibrium MCQ Question
Given the ionization constant of propanoic acid is 1.32 × 10⁻⁵, calculate the degree of ionization in a 0.05 M solution.
0.0162
0.0128
0.0216
0.0248
Correct Answer
Detailed Explanation
The degree of ionization (α) can be calculated using the formula α = √(Ka/c), where Ka is the ionization constant and c is the concentration. Substituting the given values, α = √(1.32 × 10⁻⁵ / 0.05) ≈ 0.0162.
Found an issue with this question?
Related Questions
More from Chemical Equilibrium
More from
Assertion (A): For a dibasic acid H2X, the equilibrium constant for the first ionization step (Ka1) is generally greater than that for the second ioni...
Assertion (A): The solubility of a sparingly soluble salt is affected by the presence of a common ion. | Reason (R): The solubility product constant (...
Match Column-I with Column-II. Column-I Column-II (a) Solubility Product Constant (K sp) (i) Represents maximum concentration of ions in s...