Chemistry-Chemical Equilibrium
NEET Chemistry Chemical Equilibrium MCQ Question
Type: MCQ-numerical-Hard-Class 11
Given the ionization constant of propanoic acid is 1.32 × 10⁻⁵, calculate the degree of ionization in a 0.05 M solution.
A
0.0162
B
0.0128
C
0.0216
D
0.0248
Correct Answer
Option A
Detailed Explanation
The degree of ionization (α) can be calculated using the formula α = √(Ka/c), where Ka is the ionization constant and c is the concentration. Substituting the given values, α = √(1.32 × 10⁻⁵ / 0.05) ≈ 0.0162.
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