NEET Chemistry Chemical Equilibrium Match the Following Question
Match Column-I with Column-II.
| Column-I | Column-II |
|---|---|
| (a) Ionization constant (K_a) | (i) 1.8 × 10 –5 |
| (b) pH of acetic acid solution | (ii) Degree of ionization |
| (c) Weak acid dissociation equilibrium | (iii) Dynamic equilibrium |
| (d) Hydrolysis of ammonia | (iv) K_b = 1.77 × 10 –5 |
a-i, b-ii, c-iii, d-iv
a-ii, b-i, c-iv, d-iii
a-iv, b-iii, c-i, d-ii
a-iii, b-iv, c-ii, d-i
Correct Answer
Detailed Explanation
The ionization constant of acetic acid is given as 1.8 × 10 –5, which matches with its pH being calculated based on this constant. The weak acid dissociation equilibrium represents a dynamic equilibrium, and the hydrolysis of ammonia is characterized by its K_b value of 1.77 × 10 –5.
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