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NEET 2019 Chemistry Nernst Equation MCQ Question

Type: MCQ-numerical-Medium-Class 12

For a cell involving one electron E°cell=0.59 V at 298 K, the equilibrium constant for the cell reaction is [Given that 2.303RTF=0.059 V at T=298 K\frac{2.303RT}{F} = 0.059 \text{ V at } T = 298 \text{ K}]

A

1.0 × 10⁵

B

1.0 × 10¹⁰

C

1.0 × 10³⁰

D

1.0 × 10²

Correct Answer

Option B

Detailed Explanation

Using the Nernst equation, E°cell = (0.059/n) log K, where n=1. Solving gives K = 1.0 × 10⁵.

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