NEET 2025 Chemistry Conductivity MCQ Question
If the molar conductivity (Λₘ) of a 0.050 mol L⁻¹ solution of a monobasic weak acid is 90 S cm² mol⁻¹, its extent (degree) of dissociation will be
[Assume Λₘ⁰ = 349.6 S cm² mol⁻¹ and Λ⁰ = 50.4 S cm² mol⁻¹.]
0.115
0.125
0.225
0.215
Correct Answer
Detailed Explanation
The degree of dissociation (α) is calculated using the formula α = Λₘ / Λₘ⁰. Substituting the given values, α = 90 / 349.6 = 0.257, which is closest to 0.125.
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