Calculate the average bond enthalpy of the O-H bond in a water molecule given the following bond dissociation enthalpies: H2O(g) → H(g) + OH(g); ΔaH1V = 502 kJ mol–1, OH(g) → H(g) + O(g); ΔaH2V = 427 kJ mol–1.
A
464.5 kJ mol–1
B
502 kJ mol–1
C
427 kJ mol–1
D
914 kJ mol–1

Question

Calculate the average bond enthalpy of the O-H bond in a water molecule given the following bond dissociation enthalpies: H2O(g) → H(g) + OH(g); ΔaH1V = 502 kJ mol–1, OH(g) → H(g) + O(g); ΔaH2V = 427 kJ mol–1.

A

464.5 kJ mol–1

B

502 kJ mol–1

C

427 kJ mol–1

D

914 kJ mol–1

Accepted Answer

464.5 kJ mol–1

Answer

502 kJ mol–1

Answer

427 kJ mol–1

Answer

914 kJ mol–1

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