Chemistry-Molecular Orbital Theory
NEET Chemistry Molecular Orbital Theory MCQ Question
Type: MCQ-numerical-Hard-Class 11
What is the bond order of a diatomic molecule with an electronic configuration of (σ1s)²(σ1s)²(σ2s)²(σ2s)²(π2p_x)²(π2p_y)²(σ2p_z)²(π*2p_x)¹?
A
1.5
B
2.0
C
2.5
D
3.0
Correct Answer
Option A
Detailed Explanation
Bond order is calculated as (number of electrons in bonding MOs - number of electrons in antibonding MOs)/2. Here, 10 bonding electrons and 7 antibonding electrons give a bond order of (10-7)/2 = 1.5.
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