Chemistry-Molecular Orbital Theory
NEET Chemistry Molecular Orbital Theory MCQ Question
Type: MCQ-numerical-Easy-Class 11
Calculate the bond order of a diatomic molecule with the following configuration: σ1s² σ1s² σ2p z² π2p x² π2p y² π2p x¹.
A
5
B
0
C
0
D
0.5
Correct Answer
Option A
Detailed Explanation
Bond order is calculated as (number of electrons in bonding MOs - number of electrons in antibonding MOs)/2. Here, there are 6 electrons in bonding MOs and 3 in antibonding MOs, giving a bond order of (6-3)/2 = 1.5.
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