NEET Chemistry Molecular Orbital Theory MCQ Question
For the diatomic molecule O2, the bond order can be calculated using the molecular orbital theory. If the number of electrons in bonding orbitals (Nb) is 10 and in antibonding orbitals (Na) is 6, what is the bond order?
2
1
3
1.5
Correct Answer
Detailed Explanation
Bond order is calculated as (Nb - Na) / 2. For O2, it is (10 - 6) / 2 = 2, indicating a double bond.
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