Back to Practice
NEETChemistry-Chemical Bonding and Molecular Structure

NEET Chemistry Ionic Bonding MCQ Question

Type: MCQ-conceptual-Medium-Class 11

The formation of the oxide ion, O₂−(g), from oxygen atom requires first an exothermic and then an endothermic step as shown below : O(g) + e− → O−(g); ΔH° = −141 kJ mol−1 Ω−(g) + e− → O₂−(g); ΔH° = +780 kJ mol−1 Thus, process of formation of O₂− in gas phase is unfavourable even though O₂− is isoelectronic with neon. It is due to the fact that,

A

oxygen is more electronegative

B

addition of electron in oxygen results in larger size of the ion

C

electron repulsion outweighs the stability gained by achieving noble gas configuration

D

O₂− ion has comparatively smaller size than oxygen atom.

Correct Answer

Option

Detailed Explanation

The formation of O₂− ion involves overcoming electron-electron repulsion, making the process endothermic despite achieving a noble gas configuration.

Found an issue with this question?

Related Questions

Explore More Questions

All Chemistry QuestionsChemical Bonding and Molecular Structure Questions