NEET Chemistry Covalent Bond MCQ Question
In a molecule of hydrogen fluoride (HF), if the distance between the centers of positive and negative charge is 0.9 Å and the magnitude of charge is 1.6 x 10^-19 C, what is the dipole moment (μ) of the molecule?
44 x 10^-29 C·m
44 x 10^-30 C·m
44 x 10^-28 C·m
44 x 10^-31 C·m
Correct Answer
Detailed Explanation
The dipole moment (μ) is calculated using the formula μ = charge × distance. Given the charge = 1.6 x 10^-19 C and distance = 0.9 Å = 0.9 x 10^-10 m, μ = 1.6 x 10^-19 C × 0.9 x 10^-10 m = 1.44 x 10^-29 C·m.
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