Botany-DNA Structure
NEET Botany DNA Structure MCQ Question
Type: MCQ-numerical-Hard-Class 12
If the length of E. coli DNA is 1.36 mm, calculate the number of base pairs in the E. coli DNA given that the distance between two consecutive base pairs is 0.34 nm.
A
4 million base pairs
B
3 million base pairs
C
2 million base pairs
D
5 million base pairs
Correct Answer
Option A
Detailed Explanation
The length of E. coli DNA is 1.36 mm, which is 1.36 x 10^6 nm. Using the distance between two consecutive base pairs as 0.34 nm, the number of base pairs is calculated as (1.36 x 10^6 nm) / 0.34 nm/bp = 4 million base pairs.
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