AIPMT PRELIMS2006Physics-Work, Energy and Power
AIPMT PRELIMS 2006 Physics Work Done by a Force MCQ Question
Type: MCQ-numerical-Medium-Class 11
300 J of work is done in sliding a 2 kg block up an inclined plane of height 10 m. Taking g = 10 m/s², work done against friction is:
A
50 J
B
100 J
C
zero
D
150 J
Correct Answer
Option B
Detailed Explanation
The work done against gravity is mgh = 2 kg × 10 m/s² × 10 m = 200 J. Since the total work done is 300 J, the work done against friction is 300 J - 200 J = 100 J.
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