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AIPMT PRELIMS2009Physics-Rotational Motion

AIPMT PRELIMS 2009 Physics Torque MCQ Question

Type: MCQ-conceptual-Medium-Class 11

If F⃗\vec{F} is the force acting on a particle having position vector r⃗\vec{r} and τ⃗\vec{\tau} be the torque of this force about the origin, then:

A

r⃗⋅τ⃗>0\vec{r} \cdot \vec{\tau} > 0 and F⃗⋅τ⃗<0\vec{F} \cdot \vec{\tau} < 0

B

r⃗⋅τ⃗=0\vec{r} \cdot \vec{\tau} = 0 and F⃗⋅τ⃗=0\vec{F} \cdot \vec{\tau} = 0

C

r⃗⋅τ⃗=0\vec{r} \cdot \vec{\tau} = 0 and F⃗⋅τ⃗eq0\vec{F} \cdot \vec{\tau} eq 0

D

r⃗⋅τ⃗eq0\vec{r} \cdot \vec{\tau} eq 0 and F⃗⋅τ⃗=0\vec{F} \cdot \vec{\tau} = 0

Correct Answer

Option B

Detailed Explanation

The torque τ⃗\vec{\tau} is given by r⃗×F⃗\vec{r} \times \vec{F}. If both r⃗⋅τ⃗=0\vec{r} \cdot \vec{\tau} = 0 and F⃗⋅τ⃗=0\vec{F} \cdot \vec{\tau} = 0, it implies that the torque is perpendicular to both the position vector and the force.

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