AIPMT PRELIMS 2009 Physics Conservation of Angular Momentum MCQ Question
A thin circular ring of mass M and radius R is rotating in a horizontal plane about an axis vertical to its plane with a constant angular velocity ω. If two objects each of mass m be attached gently to the opposite ends of a diameter of the ring, the ring will then rotate with an angular velocity:
ωM / (M + 2m)
ω(M + 2m) / M
ωM / (M + m)
ω(M - 2m) / (M + 2m)
Correct Answer
Detailed Explanation
Using the conservation of angular momentum, the initial angular momentum I₁ω₁ = I₂ω₂, where I₁ = MR² and I₂ = MR² + 2mR². Solving gives ω₂ = ωM / (M + 2m).
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