AIPMT PRELIMS 2010 Physics Equations of Motion MCQ Question with Solution

A particle moves a distance x in time t according to equation $x = (t + 5)^{-1}$ . The acceleration of particle is proportional to

A

$(Velocity)^{2/3}$

B

$(Velocity)^{3/2}$

C

$(Distance)^{2}$

D

$(Distance)^{-2}$

Correct Answer

Option B

Detailed Explanation

Given $x = (t + 5)^{-1}$ , velocity $v = - (t + 5)^{-2}$ , and acceleration $a = 2(t + 5)^{-3}$ . Therefore, $a \propto v^{3/2}$ .

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