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AIPMT PRELIMS2007Chemistry-Quantum Numbers

AIPMT PRELIMS 2007 Chemistry Quantum Number Rules MCQ Question

Type: MCQ-conceptual-Medium-Class 11

Consider the following sets of quantum numbers:

nlms(i)300+1/2(ii)221+1/2(iii)4321/2(iv)1011/2(v)323+1/2\begin{array}{ccccc} & \text{n} & \text{l} & \text{m} & \text{s} \\ \text{(i)} & 3 & 0 & 0 & +1/2 \\ \text{(ii)} & 2 & 2 & 1 & +1/2 \\ \text{(iii)} & 4 & 3 & -2 & -1/2 \\ \text{(iv)} & 1 & 0 & -1 & -1/2 \\ \text{(v)} & 3 & 2 & 3 & +1/2 \end{array}

Which of the following sets of quantum number is not possible?

A

(i), (ii), (iii) and (iv)

B

(ii), (iv) and (v)

C

(i) and (iii)

D

(ii), (iii) and (iv)

Correct Answer

Option A

Detailed Explanation

Quantum numbers must follow specific rules: n > l ≥ 0, m ranges from -l to +l, and s is ±1/2. Set (iv) is not possible because n cannot be 1 if l is 0 and m is1s^{-1}.

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