AIPMT-PRELIMS Chemistry Structure of Atom Class 11 Questions

Maximum number of electrons in a subshell with l = 3 and n = 4 is:

The correct set of four quantum numbers for the valence electron of rubidium atom (Z = 37) is

The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of Balmer series for a hydrogen like ion. The atomic number Z of hydrogen like ion is

The number of atomic orbitals in the fourth energy level of an atom is

If n = 6, the correct sequence of filling of electrons will be

Maximum number of electrons in a subshell of an atom is determined by the following:

Which of the following is not permissible arrangement of electrons in an atom?

The ground state energy of hydrogen atom is −13.6 eV. When its electron is in the first excited state, its excitation energy is -

If uncertainty in position and momentum are equal, then uncertainty in velocity is -

The measurement of the electron position is associated with an uncertainty in momentum, which is equal to 1 × 10⁻¹⁸ g cm s⁻¹. The uncertainty in electron velocity is : (Mass of an electron is 9 × 10⁻²⁸ g)

The total energy of electron in the ground state of hydrogen atom is –13.6 eV. The kinetic energy of an electron in the first excited state is

Consider the following sets of quantum numbers: $$\begin{array}{ccccc} & \text{n} & \text{l} & \text{m} & \text{s} \\ \text{(i)} & 3 & 0 & 0 & +1/2 \\ \text{(ii)} & 2 & 2 & 1 & +1/2 \\ \text{(iii)} & 4 & 3 & -2 & -1/2 \\ \text{(iv)} & 1 & 0 & -1 & -1/2 \\ \text{(v)} & 3 & 2 & 3 & +1/2 \end{array}$$ Which of the following sets of quantum number is not possible?

An element, X has the following isotopic composition: ²⁰⁰X : 90% ¹⁹⁹X : 8.0% ²⁰²X : 2.0% The weighted average atomic mass of the naturally occurring element X is closest to

Given : The mass of electron is 9.11 × 10⁻³¹ kg Planck constant is 6.626 × 10⁻³⁴ Js, the uncertainty involved in the measurement of velocity within a distance of 0.1 Å is :

The orientation of an atomic orbital is governed by:

The energy of second Bohr orbit of the hydrogen atom is^{-328} kJ mol⁻¹; hence the energy of fourth Bohr orbit would be:

The frequency of radiation emitted when the electron falls from n = 4 to n = 1 in a hydrogen atom will be (Given ionization energy of H = 2.18 ×10⁻¹⁸ J atom⁻¹ and h = 6.625 ×10⁻³⁴ Js):

In which of the following systems will be radius of the first orbit (n = 1) be minimum -

J.J. Thomson's cathode-ray tube experiment demonstrated that

The value of Planck's constant is 6.63 × 10⁻³⁴Js. The velocity of light is 3.0 × 10⁸ ms⁻¹. Which value is closest to the wavelength in nanometers of a quantum of light with frequency of 8 × 10¹⁵ s⁻¹:

In Hydrozen atom, energy of first excited state is - 3.4 eV. Then find out KE of same orbit of Hydrogen atom :-

General electronic configuration of lanthanides is

The following quantum no's are possible for how many orbital n = 3, ℓ = 2, m = +2

The life span of atomic hydrogen is: