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AIPMT PRELIMS2003Chemistry-Ionic Equilibrium

AIPMT PRELIMS 2003 Chemistry Solubility Product MCQ Question

Type: MCQ-numerical-Hard-Class 11

The solubility product of AgI at 25°C is 1.0×10−16 mol2 L−21.0 \times 10^{-16} \text{ mol}^2 \text{ L}^{-2}. The solubility of AgI in 10−4 N10^{-4} \text{ N} solution of KI at 25°C is approximately (in mol L−1\text{mol L}^{-1}):

A

1.0×10−161.0 \times 10^{-16}

B

1.0×10−121.0 \times 10^{-12}

C

1.0×10−101.0 \times 10^{-10}

D

1.0×10−81.0 \times 10^{-8}

Correct Answer

Option B

Detailed Explanation

The solubility of AgI in a solution containing a common ion (I⁻ from KI) is calculated using the solubility product Ksp=[Ag+][I−]K_{sp} = [\text{Ag}^+][\text{I}^-].

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