AIPMT MAINS 2010 Physics Moment of Inertia MCQ Question
From a circular disc of radius R and mass 9M, a small disc of mass M and radius R/3 is removed concentrically. The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through its centre is
40/9 MR²
MR²
4 MR²
4/9 MR²
Correct Answer
Detailed Explanation
The moment of inertia of the removed disc is subtracted from the moment of inertia of the original disc. Using the parallel axis theorem, the remaining moment of inertia is calculated.
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