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AIPMT MAINS2009Physics-Newton's Laws of Motion

AIPMT MAINS 2009 Physics Force and Acceleration MCQ Question

Type: MCQ-numerical-Medium-Class 11

A body, under the action of a force F⃗=6i^−8j^+10k^\vec{F} = 6 \hat{i} - 8 \hat{j} + 10 \hat{k}, requires an acceleration of 1 m/s². The mass of this body must be:

A

10 kg

B

20 kg

C

10√2 kg

D

2√10 kg

Correct Answer

Option C

Detailed Explanation

The magnitude of the force is calculated using F=6+(−8)2+102=10√2F = \sqrt{6^²⁺ (-8)^2 + 10^2} = 10√2. Using F=maF = ma, the mass is m=Fa=10√2m = \frac{F}{a} = 10√2 kg.

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