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AIIMS2018Physics-Semiconductors

AIIMS 2018 Physics Conductivity MCQ Question

Type: MCQ-numerical-Medium-Class 12

What is the conductivity of a semiconductor, if electron density =5×1012 / cm3= 5 \times 10^{12}\text{ / cm}^3 and hole density =8×1013 / cm3= 8 \times 10^{13}\text{ / cm}^3 (μe=2.3 m2 V−1 s−1,μh=0.01 m2 V−1 s−1\mu_e = 2.3\text{ m}^2\text{ V}^{-1}\text{ s}^{-1}, \mu_h = 0.01\text{ m}^2\text{ V}^{-1}\text{ s}^{-1})

A

5.634 Ω−1 m−15.634\ \Omega^{-1}\text{ m}^{-1}

B

1.968 Ω−1 m−11.968\ \Omega^{-1}\text{ m}^{-1}

C

3.421 Ω−1 m−13.421\ \Omega^{-1}\text{ m}^{-1}

D

8.964 Ω−1 m−18.964\ \Omega^{-1}\text{ m}^{-1}

Correct Answer

Option B

Detailed Explanation

Option B is correct because it accurately represents the calculated conductivity of the semiconductor, σ = 1.968 Ω⁻¹ m⁻¹, derived from the contributions of both electrons (nₑ, μₑ) and holes (nₕ, μₕ) in the material. The other options are not applicable as they do not provide any relevant information or values related to the conductivity calculation, which is essential for understanding the behavior of semiconductors in electronic applications. This calculation emphasizes the importance of carrier concentration and mobility in determining the electrical properties of semiconductors.

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