AIIMS 2010 Physics Work Done by a Force MCQ Question
A block of mass m is pulled along a horizontal surface by applying a force at an angle θ with the horizontal. If the block travels with a uniform velocity and has a displacement d and the coefficient of friction is μ, then the work done by the applied force is
μmgd / (cos θ + μ sin θ)
μmgd cos θ / (cos θ + μ sin θ)
μmgd sin θ / (cos θ + μ sin θ)
μmgd cos θ / (cos θ - μ sin θ)
Correct Answer
Detailed Explanation
Because the block moves with a uniform velocity, the resultant force is zero.
Found an issue with this question?
Related Questions
More from Work, Energy and Power
More from 2010
Consider the following four statements (a–d) regarding kidney transplant and select the two correct ones out of these. a. Even if a kidney transplant...
Which one of the following statements is correct with respect to AIDS?
A capillary tube of radius r is immersed in water and water rises in it to a height h. The mass of water in the capillary tube is 5 g. Another capilla...