AIIMS2019Physics-Waves

AIIMS 2019 Physics Resonance MCQ Question

Type: MCQ-numerical-Medium-Class 11

In a resonance column, first and second resonances are obtained at depths 22.7 cm22.7\text{ cm} and 70.2 cm70.2\text{ cm}. The third resonance will be obtained at a depth

A

117.7 cm117.7\text{ cm}

B

92.9 cm92.9\text{ cm}

C

115.5 cm115.5\text{ cm}

D

113.5 cm113.5\text{ cm}

Correct Answer

Option A

Detailed Explanation

To find the value of xx using equations (I) and (II), we can express l1l_1 and l2l_2 in terms of xx and the wavelength λ\lambda. From equation (I), we have l1=λ4xl_1 = \frac{\lambda}{4} - x, and from equation (II), l2=3λ4xl_2 = \frac{3\lambda}{4} - x. Substituting these into the expression for xx gives x=l232l1x = l_2 - \frac{3}{2} l_1, confirming option A.

Option B is incorrect as it does not derive from the equations provided. Option C may be a numerical solution but lacks context without specific values for l1l_1 and l2l_2. Option D does not follow from the equations given and does not relate to the calculations needed to find xx.

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