AIIMS2019Physics-Waves

AIIMS 2019 Physics Harmonic Motion MCQ Question

Type: MCQ-numerical-Medium-Class 11

Two simple harmonic motions are represented by the equations x1=5sin(2πt+π4),x2=52(sinπt+cos2πt)x_1 = 5\sin\left(2\pi t + \frac{\pi}{4}\right), x_2 = 5\sqrt{2}(\sin \pi t + \cos 2\pi t). The ratio of the amplitude of x1x_1 and x2x_2 is

A

1

B

1:21 : \sqrt{2}

C

1:21 : 2

D

1:221 : 2\sqrt{2}

Correct Answer

Option C

Detailed Explanation

The ratio of the amplitudes A1A_1 and A2A_2 is calculated as A1/A2=5/10=1/2A_1/A_2 = 5/10 = 1/2, not 1:51:5 as stated in the question. This indicates a misunderstanding of the amplitude calculation for A2A_2, which is derived from the combination of sine and cosine functions. The other options are not applicable as they do not provide relevant information or solutions to the problem. Understanding how to derive amplitudes from harmonic equations is crucial in analyzing wave phenomena in physics.

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