AIIMS 2019 Physics Simple Harmonic Motion MCQ Question

To find the amplitude $A$, we use the equation $A = \frac{\mu g}{\omega^2}$. Substituting $\mu = 0.4$, $g = 9.8 \, \text{m/s}^2$, and $\omega = \sqrt{\frac{100}{1.5}}$, we calculate $A$. The correct calculation yields $A = \frac{(0.4)(9.8)}{(\sqrt{\frac{100}{1.5}})^2} = 6 \, \text{cm}$, confirming option C. Other options are not applicable as they do not provide valid calculations or results related to the problem.