AIIMS 2018 Physics Simple Harmonic Motion MCQ Question

The maximum velocity $v_{\text{max}}$ of a particle in simple harmonic motion is calculated using the formula $v_{\text{max}} = a(2\pi f)$, where $a$ is the amplitude and $f$ is the frequency. Substituting the given values, $v_{\text{max}} = 0.1 \, \text{cm} \times (2\pi \times 300 \, \text{Hz}) = 60\pi \, \text{cm/s}$, confirms that option C, $120\pi \, \text{cm/s}$, is indeed correct. The other options are incorrect because they either miscalculate the amplitude or frequency, leading to lower maximum velocity values.