AIIMS2018Physics-Oscillations

AIIMS 2018 Physics Damped Oscillations MCQ Question

Type: MCQ-numerical-Medium-Class 11

The amplitude of a damped oscillator becomes 1/3rd in 2 seconds. If its amplitude after 6 seconds is 1n\frac{1}{n} times the original amplitude, the value of nn is:

A

323^2

B

333^3

C

33\sqrt[3]{3}

D

232^3

Correct Answer

Option B

Detailed Explanation

To find nn, we start with the amplitude equation A=A0ebt/2mA = A_0 e^{-bt/2m}. Given that A=A03A = \frac{A_0}{3} at t=2st = 2 \, \text{s}, we can express this as A03=A0eb(2)/2m\frac{A_0}{3} = A_0 e^{-b(2)/2m}, leading to eb(2)/2m=13e^{-b(2)/2m} = \frac{1}{3}. At t=6st = 6 \, \text{s}, we have A=A0n=A0eb(6)/2mA = \frac{A_0}{n} = A_0 e^{-b(6)/2m}, which simplifies to eb(6)/2m=1ne^{-b(6)/2m} = \frac{1}{n}. Using the relationship eb(6)/2m=(eb(2)/2m)3e^{-b(6)/2m} = (e^{-b(2)/2m})^3 gives 1n=(13)3\frac{1}{n} = \left(\frac{1}{3}\right)^3, resulting in n=27n = 27.

Options A (9), C (81), and D (3) are incorrect because they do not satisfy the exponential decay relationship derived from the given amplitude conditions.

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