AIIMS 2018 Physics Phase Difference MCQ Question

The phase difference between the two functions $v_1$ and $v_2$ is calculated as $\frac{\pi}{3} - \frac{\pi}{2} = -\frac{\pi}{6}$, indicating that $v_2$ lags behind $v_1$ by $\frac{\pi}{6}$ radians. This negative phase difference signifies that $v_2$ reaches its maximum or minimum value later than $v_1$, which is a critical aspect in understanding wave interactions and oscillatory motion. Other options are not applicable as they do not provide relevant information or correct phase differences related to the given functions.