AIIMS 2018 Physics Forced Vibrations MCQ Question

To find the amplitude of the particle in forced vibration, we use the formula for the amplitude $A$ given by $A = \frac{F_0}{m \omega^2}$, where $F_0$ is the amplitude of the driving force, $m$ is the mass, and $\omega$ is the angular frequency. Here, $F_0 = 100 \, \text{N}$, $m = 0.01 \, \text{kg}$ (converted from grams), and $\omega = 20\pi \, \text{rad/s}$ (since $f = 100 \, \text{Hz}$). Substituting these values gives $A = \frac{100}{0.01 \times (20\pi)^2} \approx 0.025 \, \text{m}$. Other options are incorrect as they do not match the calculated amplitude based on the provided parameters.