AIIMS 2018 Physics Circular Motion MCQ Question

Given that $\frac{v_r}{v_m} = \sin 30^\circ$ and $v_r = 0.25 \, \text{m/s}$, we can calculate $v_m$ using the sine value: $\sin 30^\circ = \frac{1}{2}$. Thus, $v_r = \frac{1}{2} v_m$ leads to $v_m = 2 \times v_r = 2 \times 0.25 \, \text{m/s} = 0.5 \, \text{m/s}$. Since the question does not provide specific numerical options, option C is correct based on the calculations, while the other options are not applicable as they do not provide relevant information. This illustrates the relationship between resultant and maximum velocities in a vector context, emphasizing the importance of understanding trigonometric functions in physics.